- #1

kontroll2007

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## Homework Statement

A proton with mass 1.45*10^-27 kg is propelled at an initial speed of 3.99*10^5 m/s directly toward a uranium nucleus 5.16 m away. The proton is repelled by the uranium nucleus with a force of magnitude F = a/x^2 where x is the separation between the two objects and a = 2.12 *10^-26 Nm2. Assume that the uranium nucleus remains at rest. What is the speed of the proton when it is 8.79 *10^-10 m from the nucleus?

Give your answer in m/s in scientific notation to three significant digits (i.e. 1.15*10^2)

Note: The numbers given in this problem do not represent actual figures, instead this is to be thought of as a theoretical calculation.

## Homework Equations

F = a/x^2

W = F*D

KE = .5*m*Vf^2-.5*m*Vi^2

## The Attempt at a Solution

F = a/x^2

F = 2.12 *10^-26/(8.79 *10^-10)^2 = 2.7438*10^-8 N

W = F*D

W = 2.7438*10^-8*(5.16 - 8.79 *10^-10) = 1.4158*10^-7 J

KE = .5*m*Vf^2-.5*m*Vi^2

1.4158*10^-7 = .5(1.45*10^-27)Vf^2-(.5)(1.45*10^-27)(3.99*10^5)^2

Vf^2 = 1.95285*10^20

Vf = 1.397410*10^10 m/s

The correct answer is supposed to be 3.55*10^5 m/s, no matter how many times I try to work this problem out I cannot every arrive at the correct value for Vf.