Solve Proton Homework: Min Speed to Miss Lower Plate

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SUMMARY

The discussion focuses on calculating the minimum speed of a proton projected between two parallel plates with an electric field of 7.8×10^5 N/C. The proton's mass is 1.67×10^−27 kg, and the plates are separated by 0.20 cm. The initial calculations incorrectly used the full separation distance instead of the midpoint, leading to an incorrect time calculation of 7.32×10^-9 s and a speed of 7.4×10^6 m/s. The correct vertical distance for the proton is 0.1 cm, which must be used to find the accurate minimum speed.

PREREQUISITES
  • Understanding of electric fields and forces (q(E) = ma)
  • Basic kinematics equations (x = vt, y = 1/2a(t^2))
  • Knowledge of proton properties (mass and charge)
  • Familiarity with unit conversions (cm to m)
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  • Review kinematics in electric fields for charged particles
  • Learn about the motion of particles in uniform electric fields
  • Study the effects of varying electric field strengths on particle trajectories
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Students in physics, particularly those studying electromagnetism and kinematics, as well as educators looking for examples of charged particle motion in electric fields.

Vanessa Avila
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Homework Statement


In the figure, a proton, mass 1.67×10^−27 kg, is projected horizontally midway between two parallel plates that are separated by 0.20cm, with an electrical field with magnitude 7.8×10^5N/C between the plates. If the plates are 5.40cm long, find the minimum speed of the proton that just misses the lower plate as it emerges from the field.
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Homework Equations


q(E) = ma
x = vt
y = 1/2a(t^2)

The Attempt at a Solution


[/B]
This is what I did:
1.6*10^-19(7.8*10^5) = 1.67*10^-27 (a)
solving for a I get: 7.47*10^13 m/s^2

then i solve for t
2*10^-3 = (1/2)(7.47*10^13)(t^2)
t = sqrt(7.47*10^13/((2)(2*10^-3))
I get 7.32*10^-9 s

then i plug that in the x = vt eqn
0.054/7.23*10^-9 = v
v = 7.4*10^6 m/s

But that is wrong
 
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It says the proton comes in midway, which means y is 0.1cm, not 0.2cm
 
Xiaochao Zheng said:
It says the proton comes in midway, which means y is 0.1cm, not 0.2cm
Oh I see.Thank you!
 

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