Solve Rotational Problem 3: Max Angle for Rod+Clay

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SUMMARY

The discussion focuses on a physics problem involving a 75 g rod and a 10 g ball of clay, where the clay impacts the rod and sticks to it. The conservation of angular momentum is applied to determine the maximum angle the rod rotates from the vertical after the impact. Key equations used include the moment of inertia calculations for both the rod and the clay, as well as the conversion of kinetic energy to potential energy. The confusion arises around the conservation of linear momentum and the interpretation of angular momentum before and after the impact.

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Homework Statement



A 75 g 30 cm long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 10g ball of clay traveling horizontally at 2.5 m/s hits and stick to the very bottom tip of the rod. To what maximum angle measured from the vertical, does the rod with attached ball of clay rotate?

Homework Equations


Angular momentum is conserved
initial L=final L
mvr=Iω
I=1/12MR^2 +mr^2
rotational K.E=1/2 Iω^2
MGh

The Attempt at a Solution


angular momentum :
0.01(2.5)(0.3)=(I1+I2)ω
Rod: I1=1/12MR^2=1/12(0.075)(0.15)^2=1.40e-04
Clay: I2=mR^2=.01(0.15)^2=2.25e-4
Initial energy =1/2 (I1+I2)ω^2

h1=.3-.3cos∅
mgh1=.01(9.8)(.3-.3cos∅)
h2=.15-.15cos∅
Mgh2=0.075(9.8)(.15-.15cos∅)
Final energy=Mgh1+mgh2
my question is only kinetic rotational energy is converted to potential energy and how come the kinetic energy is not converted to rotational energy and my teacher said the linear momentum is not conserved and I am so confused . Secondly, why the mass of initial angular momentum is small mass not the mass of clay and rod ?
 
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Anthonyphy2013 said:
Angular momentum is conserved
Only if you choose the point to take moments about such that external forces make no contribution.
angular momentum :
0.01(2.5)(0.3)=(I1+I2)ω
About what point? How far is the point of impact of the clay ball from that point?
Rod: I1=1/12MR^2=1/12(0.075)(0.15)^2=1.40e-04
It's 1/12 if R is the length of the whole rod. What length did you use above?
h1=.3-.3cos∅
What does h1 represent?
my question is only kinetic rotational energy is converted to potential energy
You can view the clay mass after impact either as rotating about the centre of the rod (so use rotational KE) or as moving linearly horizontally (briefly). They produce the same KE. These are two different ways of looking at the same thing - don't add them.
my teacher said the linear momentum is not conserved
That's right. It obviously is not conserved during impact, and it's not conserved during the subsequent rotation either because there will be a force from the axle.
Secondly, why the mass of initial angular momentum is small mass not the mass of clay and rod ?
Initial? Do you mean before or after impact? Before impact, the rod is stationary, so how would that contribute to angular momentum?
 
I have another question if the massless rod is in that case , should I consider the Kinetic energy to be the initial energy ?
 

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