Solve Smith Chart Q: Input Imp, SWR, Load Pwr

  • Thread starter Thread starter freezer
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on solving a transmission line problem using the Smith Chart, specifically for a lossless transmission line with a characteristic impedance of Z0 = 300 ohms and a load impedance of ZL = 35 + j 25 ohms. The input impedance was calculated as Zin = 1860 - j1350 ohms, and the standing wave ratio (SWR) was determined to be 9.5. Additionally, the input power to the line was estimated to be approximately 54.69W based on the load current of 1A and the load power of 35W.

PREREQUISITES
  • Understanding of Smith Chart applications in transmission line theory
  • Familiarity with complex impedance and its calculations
  • Knowledge of standing wave ratio (SWR) concepts
  • Basic electrical engineering principles, including power calculations
NEXT STEPS
  • Study the use of Smith Charts for impedance matching in RF applications
  • Learn about the calculation of input impedance for various load conditions
  • Explore the relationship between load power and input power in transmission lines
  • Investigate advanced techniques for analyzing transmission lines, such as using MATLAB or Python for simulations
USEFUL FOR

Electrical engineers, RF engineers, students studying transmission line theory, and anyone involved in impedance matching and power calculations in communication systems.

freezer
Messages
75
Reaction score
0

Homework Statement


A lossless transmission line has a characteristic impedance Z0 = 300 ohms, is 5.3 wavelength long, and is terminated in a load impedance ZL = 35 + j 25 (ohms). Find the following using Smith chart.

a) The input impedance on the line
b) The standing wave ration on the main line.
c)If the load current is 1A, calculate the input power to the line.


Homework Equations





The Attempt at a Solution



a) Zin = 300(6.2 - j4.5) = 1860 - j1350 (ohms)
b) swr = 9.5
c) I am not finding a good equation to calculate part C and not sure how you can extract this information from the chart. P= i^2 R => 35W to the load then the input would need to be 35 /0.8^2= 54.6875W
 
Physics news on Phys.org
So i can get VL = 35+j25(V)

Vl = V0+(1+gamma)
35+j25/(1.8)
V0+ = 19.44+j13.89(v)

Vin = V0+(exp(-j0.6pi) + 0.8exp(j0.6pi))
Vin = 18.89+j13.70

Iin = Vo+/Zo(exp(-j0.6pi) - 0.8exp(j0.6pi)
Iin = -1.12-j33.29
Iin* = -1.12+j33.29Pav = 0.5*Re(VI*)
1/2*Re(VinIin*)
then i get -242W (this does not seem correct)

Am i getting close?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
5
Views
10K
  • Poll Poll
  • · Replies 3 ·
Replies
3
Views
8K