Solve Solenoid Resistance/Magnetic Field/Length

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The discussion focuses on constructing a solenoid with a resistance of 9.29 ohms and a magnetic field strength of 0.0642 T when carrying a current of 7.32 A, using copper wire with a diameter of 0.895 mm. The resistivity of copper is given as 1.7 x 10-8 ohm-m. The initial calculation for the number of turns (N) was determined to be approximately 175.879 turns using the formula B = N x (μI)/(2R), but the user expressed uncertainty about its accuracy. Additionally, the length of the solenoid was calculated using R = ρl/A, resulting in an incorrect length of 34379.8 cm.

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It is desired to construct a solenoid that has a resistance of 9.29 ohm and produces a magnetic field at its center of 0.0642 T when it carries a current of 7.32 A. The solenoid is to be constructed from copper wire having a diameter 0.895 mm.
The resistivity of the copper is 1.7x10-8 ohm-m.
Find the # of turns of wire needed if the radius of the solenoid is to be 1.26 cm. Answer in units of turns.
Find the length of the solenoid. Answer in units of cm.

This is what I did:
B=N x muI/2R
.0642=N x (4pi x 10-7)(7.32)/(2*.0126)
N=175.879 turns
...But this is wrong. Can you please help me out & let me know what I did wrong?

Find the length of the solenoid. Answer in units of cm.
I used:
R=pl/A
9.29=1.7x10-8(l)/(.000895/2)^2 *pi
l=34379.8 cm
...I think this one is wrong too. Any help would be appreciated! Thanks in advance!
 
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nevermind. thanks anyway
 

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