- #1

Jamboree

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## Homework Statement

A Mass of 3.0kg is hung from a spring, causing it to stretch 12 cm at equilibrium. The 3.0kg mass is then replaced by a 4.0kg mass and the new block is released from the unstretched position. How far will the 4.0kg mass block fall before its direction is reversed?

a) 9 cm

b) 18 cm

c) 24 cm

d) 32 cm

e) 48 cm

## Homework Equations

Spring Constant-

k= F/x

## The Attempt at a Solution

First, I found the force of the 3kg block.

F= 3 * 9.8 = 29.4N

Next, I found the spring constant K

K= F/x[distance] = 29.4/.12m= 245

I Worked backwards to find the distance traveled by the 4kg block, like this.

K=F/x

245= (4*9.8)/x

x=.16m = 16 cm

Which is not one of the options. Where have I gone wrong?

Thanks for any help, it is much appreciated.