Solve T2 for the Pulling Force T3 = 98.0 N

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The problem involves three blocks connected by a cord, with a pulling force of T3 = 98.0 N. The first step is to calculate the system's acceleration using the equation that incorporates all forces, resulting in an acceleration of 1.336 m/s². This value is then used to find the tension T2 in the second block's equation, leading to a calculated tension of 60.173 N. However, there is a request for clarification on the acceleration calculation, indicating that there may be discrepancies in the values used. The discussion emphasizes the importance of accurately applying the equations of motion and friction to solve for tensions in connected systems.
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Homework Statement


1. Homework Statement
There are three blocks on a table. They are connected by a massless cord and pulled to the right. From rigt to left, it follows: T3, block 3, T2, block 2, T1, block 1
m1: 2.5kg
m2: 9.5kg
m3: 1.5kg
mu kinetic: .051
The pulling force is equal to T_3 = 98.0 N. What is the tension T_2?


Homework Equations


fnet = ma
Fapp(T3) - Fk3 - Fk2 - Fk1 = ma
T2 - Fk2 = 9.5a

The Attempt at a Solution



well firstly i tried finding the acceleration of the system using all the forces being applied.
i did Tension 3 - all the friction = ma
and acceleration comes out to be 1.336m/s^2

then i sub this back into the 2nd block system equation.

T2 - Fk2 = 9.5a
and Tension2 comes out to be 60.173N.
Is this correct? if i missed a step or did somethign wrong please correct me thanks.
 
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Your method is correct, but I don't agree with the value you got for the acceleration. Can you show exactly what numbers you put in this equation and how you solved for a?

Fapp(T3) - Fk3 - Fk2 - Fk1 = ma
 
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