Solve T2 for the Pulling Force T3 = 98.0 N

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SUMMARY

The discussion focuses on calculating the tension T2 in a system of three blocks connected by a massless cord, with a known pulling force T3 of 98.0 N. The masses of the blocks are m1 = 2.5 kg, m2 = 9.5 kg, and m3 = 1.5 kg, with a kinetic friction coefficient of μ = 0.051. The user calculated the system's acceleration as 1.336 m/s² and subsequently determined T2 to be 60.173 N. However, there is a disagreement regarding the acceleration value, prompting a request for clarification on the calculations.

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Homework Statement


1. Homework Statement
There are three blocks on a table. They are connected by a massless cord and pulled to the right. From rigt to left, it follows: T3, block 3, T2, block 2, T1, block 1
m1: 2.5kg
m2: 9.5kg
m3: 1.5kg
mu kinetic: .051
The pulling force is equal to T_3 = 98.0 N. What is the tension T_2?


Homework Equations


fnet = ma
Fapp(T3) - Fk3 - Fk2 - Fk1 = ma
T2 - Fk2 = 9.5a

The Attempt at a Solution



well firstly i tried finding the acceleration of the system using all the forces being applied.
i did Tension 3 - all the friction = ma
and acceleration comes out to be 1.336m/s^2

then i sub this back into the 2nd block system equation.

T2 - Fk2 = 9.5a
and Tension2 comes out to be 60.173N.
Is this correct? if i missed a step or did somethign wrong please correct me thanks.
 
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Your method is correct, but I don't agree with the value you got for the acceleration. Can you show exactly what numbers you put in this equation and how you solved for a?

Fapp(T3) - Fk3 - Fk2 - Fk1 = ma
 

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