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Calculus and Beyond Homework Help
Solve the given problem that involves Probability
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[QUOTE="Mark44, post: 6859915, member: 147785"] IMO, the approach above is the better approach. It uses the idea that the complement of "at least one day of the three is wet" is "none of the three days is wet." The probabilities of these two events has to add to 1. The latter approach is trickier to get right in that you have to ensure that you have included all possible events in which one, two, or three of the days is wet. In the probabilities that you list, you have omitted one. These come from the following combinations. 3 wet days: ##\binom {3}{3} = 1## -- www 2 wet days: ##\binom{3}{2} = 3## -- wwd, wdw, dww 1 wet day: ##\binom{3}{1} - 3## -- wdd, dwd, ddw [/QUOTE]
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Solve the given problem that involves Probability
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