Solve the given trigonometry problem

chwala
Gold Member
Messages
2,825
Reaction score
413
Homework Statement
##7 \sinh x + 3 \cosh x = 9##
Relevant Equations
hyperbolic trig. equations
My question is on the highlighted part (circled in red);

Why is it wrong to pre-multiply each term by ##e^x##? to realize ,

##5e^{2x} -2-9e^x=0## as opposed to factorising by ##e^{-x} ## ?

The other steps to required solution ##x=\ln 2## is quite clear and straightforward to me.



1716546593601.png
 
Physics news on Phys.org
What makes you think you cannot?
 
...because of this next step:

1716547615185.png


I think i get it now...to find the solution for ##x##, we can solve it as i had indicated but for the integration bit; we have to make use of all the transforms...
 
Last edited:
That solves an entirely different question than the one you asked. The one you asked about asked for the solutions of a particular equality. What that thing is is integrating 1 divided by one of the sides of the equality.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top