SUMMARY
The discussion centers on solving the sine equation y = -1/2sin[3(x - π/2)] - 2. The amplitude is determined to be -1/2, indicating a reflection across the x-axis. The vertical shift is confirmed as 2 units downward. The period of the function is calculated using the formula for sine functions, yielding a period of 2π/3, while the phase shift is found to be π/2 units to the right.
PREREQUISITES
- Understanding of sine functions and their properties
- Familiarity with amplitude and vertical shift concepts
- Knowledge of period and phase shift calculations
- Basic algebra skills for manipulating equations
NEXT STEPS
- Study the derivation of the period of sine functions
- Learn about transformations of trigonometric functions
- Explore the effects of negative amplitudes on sine graphs
- Practice solving similar sine equations with varying parameters
USEFUL FOR
Students studying trigonometry, educators teaching sine functions, and anyone looking to deepen their understanding of wave properties in mathematics.