Solve this differential equation using separation of variables

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The discussion focuses on solving the differential equation dy/dx = y^2 x using separation of variables, with the initial condition y = -1 when x = 0. A participant struggles to arrive at the correct solution, y = -2/x^2 + 2, after separating variables and integrating. The correct approach involves rewriting y^2 as 1/y^2 during separation, leading to (1/y^2)dy = x dx. Clarification is provided that the "1" in 1/y^2 comes from dividing both sides by y^2, which is essential for proper integration. The thread emphasizes the importance of correctly applying separation of variables to reach the solution.
escobar147
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Solve the following first order, ordinary differential equations using separation of variables:

dy/dx = y^2 x

subject to y=-1 when x=0

the correct answer is: y = -2/x^2 + 2

i cannot seem to get this answer, after i separate the variables and integrate both sides i get:

y^2 x^2/2

then if i plug the values in i get y = 0?

please help
 
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When you separate the variables you should get

(1/y^2)dy = x dx

Integrating 1/y^2 wrt y will not give you y^2. Rewrite it as y^-2.
 
rock.freak667 said:
When you separate the variables you should get

(1/y^2)dy = x dx

Integrating 1/y^2 wrt y will not give you y^2. Rewrite it as y^-2.

hi, thanks foryour reply i appreciate it, but could you please explain why when you separate variables y^2 become 1/y^2?
 
dy/dx = y2 x

Divide both sides by y2

(1/y2)dy/dx = x
 
rock.freak667 said:
dy/dx = y2 x

Divide both sides by y2

(1/y2)dy/dx = x

where has the 1 come from? is it the coefficiant of dy/dx?
 
escobar147 said:
where has the 1 come from? is it the coefficiant of dy/dx?

Well you can think of the 1 like that yes.
 
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