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Solve Using Frobenius Method
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[QUOTE="vanhees71, post: 4526167, member: 260864"] It's nearly correct (as far as I can infer from the analytic solution, I got with Mathematica, and which you will easily find when you have completed your work with the Frobenius method). You simply forgot the first thing you always should figure out first, namely to get [itex]s[/itex]! In the most simple case you should get two solutions for [itex]s[/itex] and your method of comparison of coefficients gives the solution as a (generalized power series) for each of these solutions (there are exceptions, where in this way you get only one solution, but this is not the case here) and you found then two linearly independent solutions of your 2nd-order ODE and thus already the general solution. In your case you can even resum the very simple series to closed analystical expressions. [/QUOTE]
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Solve Using Frobenius Method
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