MHB Solve Work Rate Problem: Find A and B's Time Alone

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To solve the work rate problem, "A" takes two hours longer than "B" to complete a job. After "B" works alone for one hour, both work together for three additional hours to finish the job. The equations derived indicate that "B" requires 6 hours to complete the job alone, while "A" requires 8 hours. The discussion emphasizes the necessity of using time and rate equations to find the solution. Overall, the approach taken is deemed effective for solving the problem.
Drain Brain
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I just want an alternative solution(preferably easier approach) to this problem

"A" can finish a job two hours longer than "B". After working for 1 hour, "B" joins him and they complete the job in 3 more hours. How long would it take "A" and "B" to finish a similar job if each worked alone?

my solution,

Let $B+2=$ A's required time to finish the job alone
$B=$ B's required time to finish the job alone

$\frac{1}{B+2}+3\left(\frac{1}{B+2}+\frac{1}{B}\right)=1$

solving for B I have

$B=6$hours
$A=8$hours

Regards!:)
 
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Well, I don't think there could be a much simpler way to solve this problem. You've got to work with times and rates like you're doing. There are two unknowns, which means you'd have to have two equations.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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