Spruance Messages 33 Reaction score 0 Thread starter Apr 23, 2006 #1 How do we solve this equation: x^2 + (-1/2x + 5)^2 = 25 Thanks in advance
Doc Al Mentor Messages 45,587 Reaction score 2,469 Apr 23, 2006 #2 Expand that squared term and you'll see that this quadratic equation simplifies nicely.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Apr 23, 2006 #3 That's assuming that you mean ((-1/2)x + 5)^2 and not (-1/(2x)+ 5)^2.
Spruance Messages 33 Reaction score 0 Apr 23, 2006 #4 Thanks, then x^2 + (-x/2 + 5)^2 = 25 x2 + x2/4 - 5x + 25 = 25 5x2/4 - 5x = 0 (* 4/5) x2 - 4x = 0 x(x - 4) = 0 x = 0 or x = 4.
Thanks, then x^2 + (-x/2 + 5)^2 = 25 x2 + x2/4 - 5x + 25 = 25 5x2/4 - 5x = 0 (* 4/5) x2 - 4x = 0 x(x - 4) = 0 x = 0 or x = 4.