Solved: Find Solutions for Group Theory Problem in Z_12

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Homework Help Overview

The discussion revolves around finding all solutions to the equation x^3-2x^2-3x=0 in the context of the ring Z_12, which is not an integral domain due to its composite nature.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss factoring the polynomial and the implications of working within Z_12, noting that setting factors to zero may not yield all solutions. There are suggestions to utilize the Chinese remainder theorem and to consider smaller rings like Z/2Z and Z/4Z. Additionally, the idea of testing all possible values in Z_12 is raised as a potential approach.

Discussion Status

The discussion is active, with participants exploring various methods to approach the problem. Some guidance has been offered regarding the use of prime factorization and the Chinese remainder theorem, while others are questioning the completeness of the initial attempts to find solutions.

Contextual Notes

There is an acknowledgment of the limitations of Z_12 as a non-integral domain, which affects the approach to finding solutions. The participants are also considering the implications of zero divisors in their reasoning.

ehrenfest
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[SOLVED] group theory problem

Homework Statement


Find all solutions of the equation x^3-2x^2-3x=0 in Z_12.


Homework Equations





The Attempt at a Solution


We first factor the polynomial into x(x-3)(x+1)=0. Recall that Z_12 is not an integral domain since 12 is not prime (e.g. 3*4=0). Therefore setting each factor equal to 0 WILL NOT GIVE ALL OF THE SOLUTIONS.

Obviously, the solutions to x=0, (x-3)=0, (x+1)=0, x(x-3)=0, x(x+1) = 0, (x-3)(x+1)=0 will also be solutions to our equation. I can find all of those. The problem is that I do not know how to find the remaining ones.
 
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You could narrow things down by factoring 12 into prime powers, and using the chinese remainder theorem.

You can narrow things down even further in Z/4Z by first considering it in Z/2Z.


Or... you could apply the fact that each solutions will make at least one of the factors a zero divisor..


But honestly, 12 is so small that I'd expect simply trying all 12 possibilities is the most efficient way to find the roots.
 
Last edited:
Hurkyl said:
But honestly, 12 is so small that I'd expect simply trying all 12 possibilities is the most efficient way to find the roots.

What are the twelve possibilities?
 
ehrenfest said:
What are the twelve possibilities?

x=0,1,2...11. What else??
 
From what you said before, it would appear that you know what Z12 is! The" 12 possibilities" Hurkyl mentioned are the 12 elements of that ring.
 
Grrrr. Someday I will stop making mistakes like this.
 

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