- #1

ArcadianGenesis

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## Homework Statement

A man jumps from the top of a building to the top of another building 3.7 meters away. After a running start he leaps at an angle of 14 degrees with respect to the flat roof while traveling at a speed of 5.1 m/s. The acceleration of gravity is 9.81 m/s/s. To determine if he will make it to the other roof, which is 1.1 meters shorter than the building from which he jumps, find his vertical displacement upon reaching the front edge of the lower building with respect to the taller building.

## Homework Equations

y = v[tex]_{}oy[/tex]t - (1/2)gt[tex]^{}2[/tex]

x = v[tex]_{}ox[/tex]t

## The Attempt at a Solution

3.7 = 5.1cos14t

t = 3.7/5.1cos14

y = 5.1sin14(.7) - (1/2)(9.81)(.7[tex]^{}2[/tex])

y = -1.54

The answer sounds reasonable - what could possibly be wrong?