How Can You Integrate (4X^3-7X^2+6X-3)/(X^6-4X^3) by Hand?

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SUMMARY

The integration of the function (4X^3-7X^2+6X-3)/(X^6-4X^3) by hand can be approached using partial fractions. The original poster encountered difficulties due to a simplification error, leading to incorrect equations for the coefficients. Correctly applying the method of partial fractions requires careful attention to the algebraic manipulation of the terms involved. The final integration result provided by the TI-89 calculator indicates a complex expression involving logarithmic and arctangent functions.

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thharrimw
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How colud you intergrate (4X^3-7X^2+6X-3)/(X^6-4X^3) by hand (my TI-89 gave me -[2(13*2^(1/3)-12)(√3*2^(1/3))X^2*Arctan[√3-*2^(1/3)(2X+2^(2/3))/6]+2^(2/3)+28√2+13)X^2ln(X62+2^2/3X+X^(4/3)+2(2^(1/3)(14*2^(2/3)*X^2ln|X-2^(2/3)|-6(14X^2ln|X|)+2(4X-1)))))]\96X^2
i tryed to use partial fractions but i couldn't solve it using partial fractions so i have no idea of where to start.
 
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partial fractions works fine, what went wrong?
 
never mind I messed up on my simplification i put a extra variable when i simplified so i got
0=A+E,
4=B+D,
-7=C-4E,
6=4D+E,
-3=-4c+A,
insted of
0=A+E,
4=B+D,
-7=C-4E,
6=4D,
-3=-4c,
 

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