Solving 6kg Cat on Wagon Mass Problem

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SUMMARY

The discussion centers on solving a physics problem involving a 6-kilogram cat walking on a stationary cart. The key equation derived is the conservation of momentum, expressed as mcatvcat + mcartvcart = 0. The cat moves at 1 m/s while the cart moves backward at 3 m/s, leading to the conclusion that the mass of the cart can be calculated using these velocities and the mass of the cat. The importance of considering direction in momentum calculations is emphasized.

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Homework Statement



If a 6 kilogram cat walks on a stationary cart 1 m/s straight and then the wagon moves back at a speed of 3 m/s what's the mass of the cart?

Homework Equations


The Attempt at a Solution



I was thinking it would be a momentum problem, so mv of cat = mv of cart

I'm not sure I got this right...
 
Last edited:
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I Like Pi said:
I was thinking it would be a momentum problem, so mv of cat = mv of cart
Assuming that both the cat and the cart are at rest when the cat is not walking, yes, I agree with you. :approve:
 
Just for clarity though, Be careful about direction. What I should clarified in my last post is

mcatvcat + mcartvcart = 0,

where the velocities can be positive or negative, depending on the direction.
 

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