Solving a 2nd order ODE with variable coefficients

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The discussion focuses on solving the second-order ordinary differential equation x^2 y'' + xy' + (4x^2 - 1)y = 0 using Frobenius' method. Participants suggest expressing the solution as a power series and determining the appropriate value of c to ensure the coefficient for n=0 is non-zero. It is noted that the solution can be related to Bessel functions through a substitution of the independent variable. Although the professor indicated that this topic has not yet been covered in class, prior knowledge of generating functions may assist in finding a solution. The thread emphasizes the complexity of the equation and the need for further research.
AdrianZ
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Homework Statement



the problem is to solve this differential equation:

x^2 y'' + xy' + (4x^2 - 1)y = 0
 
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I would recommend Frobenius' method, writing a solution as
y(x)= \sum_{n=0}^\infty a_nx^{n+c}
Find y'' and y' for that, put into the equation. Choose c (it is not necessarily a positive integer) such that the n= 0 coefficient is non-zero.
 
The solution is expressible in terms of Bessel functions, but you need to make the substitution:
<br /> t = a x<br />
for the independent variable with a suitable choice of a.
 
Actually this is a question for extra points. We haven't reached to Bessel function or Frobenius' method but the professor told us that if some of us have already passed discrete mathematics and known about generating functions then with doing some research on it we might be able to solve it although it's not an easy equation as he said. I tried to take the series that HallsofIvy suggested but didn't succeed to solve the problem.+ How can I find the value of c?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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