MHB Solving a Boundary Value Problem: Non-Uniform vs. Uniform Partitioning

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SUMMARY

The discussion focuses on solving a boundary value problem (BVP) represented by the equation $-\epsilon u'' + u' = 1$ on the interval $[0,1]$, where $\epsilon$ is a positive constant. The exact solution is derived through substitution and integration, yielding $u(x) = x + \frac{e^{x/\varepsilon} - 1}{1 - e^{1/\varepsilon}}$. The conversation emphasizes the importance of comparing numerical solutions obtained via finite difference methods using both non-uniform and uniform partitioning to determine which approach yields better accuracy.

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evinda
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Hello! (Wave)Consider the boundary value problem
$\left\{\begin{matrix}
- \epsilon u''+u'=1 &, x \in [0,1] \\
u(0)=u(1)=0 &
\end{matrix}\right.$
where $\epsilon$ is a positive given constant.
I have to express a finite difference method for its numerical solution.
How can we know whether it is better to use non-uniform partition or uniform partition?
 
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Well, you can always do the experiment and see. This BVP has an exact answer that's not too difficult to obtain. If you do the substitution $v=u'$, you get a first-order linear DE, $v'-v/\varepsilon=-1/\varepsilon$, with solution
$$v=1+C_1 e^{x/\varepsilon}.$$
Integrating once yields
$$u=x+\varepsilon C_1 e^{x/\varepsilon}+C_2.$$
Applying the boundary conditions yields the system
\begin{align*}
\varepsilon C_1+C_2&=0 \\
\varepsilon C_1 e^{1/\varepsilon}+C_2&=-1,
\end{align*}
with solution
\begin{align*}
C_1&=\frac{1}{\varepsilon(1-e^{1/\varepsilon})} \\
C_2&=\frac{1}{e^{1/\varepsilon}-1}.
\end{align*}
Hence, the exact solution is
$$u(x)=x+\frac{e^{x/\varepsilon}-1}{1-e^{1/\varepsilon}}.$$
You can use this to compare how good the two numerical solutions are.
 

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