Solving a convex mirror problem

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SUMMARY

The discussion centers on solving a convex mirror problem involving a focal length of 12.5 meters, an object height of 5 meters, and an image height of 1 meter. The key equations used are the mirror formula (1/f = 1/do + 1/di) and the magnification formula (magnification = -hi/ho = di/do). The correct solutions derived from the equations are an object distance (do) of 50 meters and an image distance (di) of -10 meters, indicating that the image is virtual and located behind the mirror.

PREREQUISITES
  • Understanding of convex mirrors and their properties
  • Familiarity with the mirror formula (1/f = 1/do + 1/di)
  • Knowledge of magnification concepts in optics
  • Basic algebra skills for rearranging equations
NEXT STEPS
  • Study the properties of convex mirrors in optics
  • Practice solving problems using the mirror formula
  • Explore the concept of virtual images and their characteristics
  • Learn about the applications of convex mirrors in real-world scenarios
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Students studying optics, physics educators, and anyone seeking to understand the principles of convex mirrors and their mathematical applications.

Jack.P
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Homework Statement



Given the following information: convex mirror, focal length (f) = 12.5 metres, height object (ho) = 5 metres, height image (hi) = 1 metre. Find distance object (do) and distance image (di).

Homework Equations



1/f = 1/do + 1/di

Magnification= -hi/ho = di/do


The Attempt at a Solution



I found that the magnification is -0.2.

Rearranging the magnification equation I found that di=-0.2do
and that
do=-5di

My intention was to substitute one of the two into 1/f = 1/do + 1/di

I tried to make the denominators equal after substituting in di=-0.2do however my answer was incorrect.

Correct answers are do = 50 metres, di = -10 metres

I don't understand how to mathematically solve this problem. Any help would be greatfully appreciated.
 
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What was your answer?

I think your approach was right so maybe you just made an arithmetic mistake.
 

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