Solving a Differential Equation with Integrating Factors

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The discussion focuses on solving the differential equation (x+1)y' + 2y - (x+1)^(5/2) = 0. Participants suggest using a particular solution of the form y_p = a(x+1)^b and solving the associated homogeneous equation to find the general solution. The method of integrating factors is mentioned as a potential approach for solving first-order linear differential equations. One user expresses difficulty with the problem, indicating they are new to this topic and seeking simpler methods. The conversation highlights the importance of understanding integrating factors for tackling such equations effectively.
CalculusHelp1
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Homework Statement



Find the solution to (x+1)y' +2y -(x+1)^(5/2)=0

Homework Equations



Definiton of antiderivative


The Attempt at a Solution



I have been trying to manipulate this equation in every possible way so that I can get x on one side and y on the other. Ever attempt has led to a dead end. I tried to factor the (x+1) terms, tried to carry things over to the other side, nothing is working.

Can anyone give me a nod in the right direction so I can tackle this problem? Thanks
 
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For a particular solution, you might try

y_p = a (x+1)^b,

where there's an obvious guess for b if you think a bit before doing any calculations. Otherwise, plug this in and see what values of b and a solve the equation.

To get the full solution, you also have to solve the homogeneous equation

(x+1)y' +2y =0

which will give you a function y_h(x). The general solution to the original equation is y=y_h + y_p.
 
Multiply by (x+1), then notice that:

\frac{d}{dx}\left((x+1)^2y\right)=(x+1)^2y'+2(x+1)y
 
Okay this problem might be over my head. I've only just learned first order linear differential equations and solving them by separation of variables.

Is there any easier way to do this?
 
CalculusHelp1 said:
Okay this problem might be over my head. I've only just learned first order linear differential equations and solving them by separation of variables.

Is there any easier way to do this?

Have you learned about integrating factors?
 
No, what are those?
 
CalculusHelp1 said:
No, what are those?

I could give a reasonably good answer, but Paul of Paul's Online Math Notes does a better job. Just Google : "integrating factors, pauls online math notes"
 

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