Solving a Double Quadratic Equation: Finding n+m

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thereddevils
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Homework Statement



4n^2+9m^2-240n-720m+18000=0

Find n+m

Homework Equations





The Attempt at a Solution



I try to express the equation in the form of a(n+m)^2-b(n+m)+c=0 but i couldn't find a way to do so .
 
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What calculations have you done so far? If you show what attempts you've made so far then can see how it's going. :smile:
 
Axiom17 said:
What calculations have you done so far? If you show what attempts you've made so far then can see how it's going. :smile:

Thanks for replying here , i hv got it solved.

Just express it in the form Ehild suggested and the values of m and n will be b and a respectively.
 
can someone pls show me the full step working?
 
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0
 
cycy said:
can someone pls show me the full step working?
Sorry, but at this forum that is not how we give help.

cycy said:
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0
Try expanding that expression first. Then you can compare it to the original equation.
 
cycy said:
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0

I wasn't answering anything, I was asking you a question. If you know how to complete the square then this problem isn't too difficult at all.

I just wanted to know where to start helping you, but I don't think you really deserve any unless you clean up your attitude mate.