Solving a Double Quadratic Equation: Finding n+m

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Homework Help Overview

The problem involves solving a double quadratic equation of the form 4n² + 9m² - 240n - 720m + 18000 = 0, with the goal of finding the sum n + m.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss expressing the equation in different forms, such as (n+m)² and completing the square. Some question how to eliminate the constant term 18000 from the equation.

Discussion Status

There is a mix of attempts to clarify the problem and explore different methods. Some participants have suggested approaches, while others express uncertainty about their understanding of completing the square. The discussion reflects a range of interpretations and attempts without a clear consensus on the solution.

Contextual Notes

Participants have noted the challenge of manipulating the equation to facilitate solving for n and m, particularly regarding the constant term. There is an indication of imposed homework rules that limit the type of assistance that can be provided.

thereddevils
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Homework Statement



4n^2+9m^2-240n-720m+18000=0

Find n+m

Homework Equations





The Attempt at a Solution



I try to express the equation in the form of a(n+m)^2-b(n+m)+c=0 but i couldn't find a way to do so .
 
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The expression can be written in the form of 4(n-a)^2+9(m-b)^2=0


ehild
 
What calculations have you done so far? If you show what attempts you've made so far then can see how it's going. :smile:
 
Axiom17 said:
What calculations have you done so far? If you show what attempts you've made so far then can see how it's going. :smile:

Thanks for replying here , i hv got it solved.

Just express it in the form Ehild suggested and the values of m and n will be b and a respectively.
 
OK great :smile:
 
can someone pls show me the full step working?
 
cycy said:
can someone pls show me the full step working?

Do you know how to complete the square?
 
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0
 
cycy said:
can someone pls show me the full step working?
Sorry, but at this forum that is not how we give help.

cycy said:
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0
Try expanding that expression first. Then you can compare it to the original equation.
 
  • #10
cycy said:
thanks for answering...
not really...
i'm just wondering how to get rid of the constant,18000,if we express it as 4(n-a)^2+9(m-b)^2=0

I wasn't answering anything, I was asking you a question. If you know how to complete the square then this problem isn't too difficult at all.

I just wanted to know where to start helping you, but I don't think you really deserve any unless you clean up your attitude mate.
 
  • #11
i have solved it...
 

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