Solving a Logarithmic Equation: Log(5) X = 1/2Log(5) 25

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Homework Help Overview

The discussion revolves around solving a logarithmic equation involving the base 5 logarithm, specifically Log5 X = 1/2 Log5 25. Participants are attempting to clarify the steps involved in manipulating logarithmic expressions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Some participants express confusion regarding the manipulation of logarithmic terms and question the validity of certain steps taken in the original poster's approach. Others suggest alternative methods for simplifying the equation, including rewriting logarithmic expressions.

Discussion Status

The discussion features a mix of attempts to clarify the original poster's reasoning and corrections from other participants. While some assert that the calculations presented are correct, others emphasize the importance of understanding the foundational concepts of logarithms. There is no explicit consensus on the best approach, but several lines of reasoning are being explored.

Contextual Notes

Participants are navigating through potential misunderstandings of logarithmic properties and the implications of their calculations. There is an underlying tension regarding the tone of feedback, with some comments reflecting a need for constructive criticism.

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Homework Statement



solve:Log(subscript 5) X = 1/2log(subscript 5) 25

Homework Equations





3. The Attempt at a Solution [/
Log(subscript 5) X = 1/2log(subscript 5) 25
--------------- ---------------------
Log(subscript 5) Log(subscript 5)


Then they cancel out and I got X = 1/2Log(subscript 5) 25
-----------------------
Log(subscript 5)

That's what I got but I'm not sure if its right. Please help

It looks weird but i hope you understand what I'm trying to show you.
 
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It doesn't work that way!

[tex]log_5 x = (1/2)(log_5 25)[/tex]
[tex]log_5 x = (1/2) 2[/tex]
[tex]log_5 x = 1[/tex]

Please learn the basics and stuff... it will help!
 
I would have done it a slightly different way:
[tex]log_5(X)= \frac{1}{2}log_5(25)[/tex]
[tex]log_5(X)= log_5(25^{\frac{1}{2}})[/tex]
[tex]log_5(X)= log_5(5)[/tex]
Now it should be easy to see what X is.
 
siddharthmishra19 said:
It doesn't work that way!

[tex]log_5 x = (1/2)(log_5 25)[/tex]
[tex]log_5 x = (1/2) 2[/tex]
[tex]log_5 x = 1[/tex]

Please learn the basics and stuff... it will help!

Learn the basics yourself, you got it wrong! jk
 
siddharthmishra19 said:
It doesn't work that way!

[tex]log_5 x = (1/2)(log_5 25)[/tex]
[tex]log_5 x = (1/2) 2[/tex]
[tex]log_5 x = 1[/tex]

Please learn the basics and stuff... it will help!

Corkery said:
Learn the basics yourself, you got it wrong! jk
No, while his statement about learning the basics is a little harsh (though true), his calculation is exactly correct. log5(25)= 2 so (1/2)log5(25)= 1. log5(x)= 1 so x= 1.

You may need to review yourself!
 
HallsofIvy said:
No, while his statement about learning the basics is a little harsh (though true), his calculation is exactly correct. log5(25)= 2 so (1/2)log5(25)= 1. log5(x)= 1 so x= 1.

You may need to review yourself!

well in that case I am really sorry! But its not like i meant it in a hatefl way. Sorry once again.:frown:
 
I didn't think you did. But be careful, in the future, about telling someone else he is wrong. Especially without explaining exactly HOW it is wrong!

I've started, many times, to tell someone he was wrong, and while writing out exactly WHY he was wrong said "oops" and kept my mouth shut!
 
HallsofIvy said:
I didn't think you did. But be careful, in the future, about telling someone else he is wrong. Especially without explaining exactly HOW it is wrong!

I've started, many times, to tell someone he was wrong, and while writing out exactly WHY he was wrong said "oops" and kept my mouth shut!

Speaking of "oops", I'm sure you meant x=5 (as you had a couple posts before.)
 

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