Solving a Physics Quiz: Calculate the Temperature Rise

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SUMMARY

The discussion revolves around calculating the temperature rise of a 0.5 kg rock dropped from a height of 20 meters into a pail containing 0.6 kg of water. The specific heat of the rock is 1480 J/kg·K, while the specific heat of water is 4186 J/kg·K. The temperature rise can be determined using the principles of energy conservation, specifically the conversion of gravitational potential energy into thermal energy. The final temperature can be calculated using the formula Q = mcΔT, where Q is the heat transferred, m is mass, c is specific heat, and ΔT is the change in temperature.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Knowledge of specific heat capacity
  • Familiarity with the formula Q = mcΔT
  • Basic principles of thermodynamics
NEXT STEPS
  • Study the concept of gravitational potential energy and its calculations
  • Learn about specific heat capacity and its applications in thermal energy transfer
  • Explore the principles of energy conservation in thermodynamic systems
  • Practice solving problems involving heat transfer between different materials
USEFUL FOR

Students studying physics, educators teaching thermodynamics, and anyone interested in understanding energy transfer in physical systems.

Sheldinoh
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My Physics teacher gave us a quiz problem and I don't understand it really how he got his answer. Can you please give me your answer and an explanation for the answer Thanks. Here is the question:

A .5 kg rock is dropped from a height of 20 meters into a pail containing .6 kg of water. The rock has a specific heat of 1480 and the water has a specific heat of 4186. What is the is the rise in temperature of the rock and water ?
 
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What do you think happened when the rock dropped??
 

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