What is the is the rise in temperature of the rock

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Homework Help Overview

The problem involves a rock being dropped into water, focusing on the rise in temperature of both the rock and the water after the impact. It deals with concepts of energy transfer, specifically potential energy converting to thermal energy.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the energy conservation principles involved, questioning the correct formulation of the energy balance equation. There is a focus on how to account for the energy transfer between the rock and the water.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the energy equations. Some guidance has been provided regarding the assumptions about initial temperatures and the energy changes involved, but no consensus has been reached on the correct approach.

Contextual Notes

There is uncertainty regarding the initial temperatures of the rock and water, which may affect the energy transfer calculations. Participants are also navigating differing opinions on the correct formulation of the energy balance equation.

Sheldinoh
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My Physics teacher gave us a quiz problem and I don't understand it really how he got his answer. Can you please give me your answer and an explanation for the answer Thanks. Here is the question:

A .5 kg rock is dropped from a height of 20 meters into a pail containing .6 kg of water. The rock has a specific heat of 1480 and the water has a specific heat of 4186. What is the is the rise in temperature of the rock and water ?
 
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Show what you have tried already.
 


I think it is:
mgh(energy of fall ) = mcT + mcT


My teacher says its:
mgh + mcT = mcT
 


.In terms of energy changes PE changes to KE and then to heat in both the water and the rock.It is not necessary to calculate the KE so go straight to your equation which is the correct one.Make sure you plug in the right values for m and c.
 


Thanks for agreeing with me. Could you help me out now with making my physics teacher agree with me. He says that you add the energy of the rock with the heat from the rock to equal the heat of the water. mgh+mcT(rock)=mcT(water). I think it is wrong but I have no clue how to explain it. Do you know how.
 


The impression gained from your question was that the rock and water were both at the same temperature at the start. Let us assume they are not.
If the rock were colder then it would gain some of its heat energy from the heat energy of the water and if the water were colder it would gain some of its heat energy from the heat energy rock.If they were at the same temperature, which is what I assume from your question,then both would gain heat energy from the PE only and both of them would heat up.
 

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