Solving a Pulley Problem: Finding Rope Tension

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SUMMARY

The discussion focuses on calculating the tension in a rope connected to two masses, 10 kg (M) and 2.5 kg (m), over a frictionless pulley. The user correctly identifies the forces acting on the masses and calculates the acceleration as 1.962 m/s² using the formula A = F/M, where F is the net force and M is the total mass. The tension in the rope can be determined using the equation T = m(g + a) for the 2.5 kg mass, where g is the acceleration due to gravity (9.81 m/s²). The confusion arises from the application of the tension formula and the forces acting on the masses.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Basic knowledge of gravitational force calculations
  • Familiarity with pulley systems and tension concepts
  • Ability to perform basic algebraic manipulations
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  • Study the derivation of tension in pulley systems with multiple masses
  • Learn about the effects of friction in pulley problems
  • Explore advanced dynamics involving multiple pulleys
  • Investigate real-world applications of tension in engineering scenarios
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Students studying physics, engineers working with mechanical systems, and anyone interested in understanding dynamics and tension in pulley systems.

Oliviam12
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I have a question on a pulley problem; the problem looks like this:

M (10) ...O
------------|...
xxxxxxxxxxxx|...
xxxxxxxxxxxx|m (2.5)
xxxxxxxxxxxx|...
With the: O being a frictionless pulley
- being solid ground
. Being a rope
M a mass of 10 kg
m a mass of 2.5 kg

I need to find the tension in the rope.

I have found the acceleration of the masses by:
FM=ma
=10*0
=0 N

Fm=2.5 *9.81
Fm= 24.525 N

A=F/M
A=(24.525 N)/ (10+2.5)
A= 1.962 m/s^2

I know I need to use the equation T= m(g+a) or T=m(g-a) but, I am not sure which one or what mass I am supposed to use. (maybe 2.5 kg?)
 
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I don't understand these parts:

"FM=ma
=10*0
=0 N"

"Fm=2.5 *9.81
Fm= 24.525 N"

24.525 is the force of gravity on m... is that what you meant here?

You have the right acceleration... The top mass has only one force acting on it.. tension... so Tension = ma
 

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