Solving a Rainforest Biologist's Homework Problem

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SUMMARY

The discussion centers on a physics homework problem involving a rain forest biologist pulling a 50 kg crate of bananas using a pulley system. The biologist must calculate the work done on the crate and the potential energy at the top of an 80 m tree. The work-energy theorem is applicable, where the work done equals the change in energy. The potential energy at the top is calculated using the combined mass of the crate and the monkey, which totals 100 kg.

PREREQUISITES
  • Understanding of the work-energy theorem
  • Knowledge of gravitational potential energy calculations
  • Familiarity with basic physics concepts such as mass and height
  • Ability to perform unit conversions and calculations involving meters and kilograms
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn how to calculate gravitational potential energy using the formula PE = mgh
  • Explore pulley systems and their mechanical advantages
  • Practice solving similar physics problems involving multiple masses and heights
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of applying the work-energy theorem in real-world scenarios.

sweedeljoseph

Homework Statement


A rain forest biologist is pulling a 50 kg crate of bananas at a constant rate from the ground to the canopy with a rope on a pulley. The distance that the crate has to go is 80 m. When the crate has traveled 40 m, a monkey with a mass of 50 kg jumps on to the top of the crate, and rides on the crate the rest of the way up.
a) How much work does the biologist do on the crate?
b) How much potential energy does the crate have at the top of the tree?

Homework Equations


Wgrav=mg(ho-hi)
PEgrav=mgh

The Attempt at a Solution


i remember doing something like this in class before. but there was more than just this. i forgot how to do it though. are you supposed to do it twice then add or something. because another thing is added. like for work you have the normal then when the monkey on it its more. would you just add those together? for the potential energy for the mass you would add both the monkey and the crate? and for the height you would just use the full? you wouldn't use the middle when the monkey jumped on because it wants it at the top right?

thank you!
sweedeljoseph
 
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sweedeljoseph said:
A rain forest biologist is pulling a 50 kg crate of bananas at a constant rate from the ground to the canopy with a rope on a pulley. The distance that the crate has to go is 80 m. When the crate has traveled 40 m, a monkey with a mass of 50 kg jumps on to the top of the crate, and rides on the crate the rest of the way up.
a) How much work does the biologist do on the crate

Hi sweedeljoseph! :smile:

Just use the work-energy theorem …

work done = change in energy. :smile:
 

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