Solving a Real-Valued Differentiable Function Problem

Click For Summary

Homework Help Overview

The problem involves a real-valued differentiable function with the property that f(x) = f(-x), indicating it is an even function. Given specific values for the function and its derivative at certain points, participants are tasked with finding additional derivatives and the intersection of tangent lines to the function's graph.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of the function being even, particularly in relation to its derivative at zero. There is mention of constructing tangent lines based on symmetry and the information provided.

Discussion Status

Some participants have made progress on the first part of the problem, while others are exploring the implications of the even function property for the remaining parts. Guidance has been offered regarding the use of symmetry and properties of derivatives, but no consensus has been reached on the remaining questions.

Contextual Notes

There is an assumption that the participants are familiar with the properties of even functions and their derivatives, which may influence their approaches. The specific values provided for the function and its derivative at certain points are critical to the discussion.

ludi_srbin
Messages
137
Reaction score
0
Alright, here is the problem.

For all real numbers x, f is differentiable function such that f(x)=f(-x). Let f(p)=1 and f'(-p)=5, for some p>0

a) Find f'(-p)

b) f'(0)

c) If L1 and L2 are lines tangent to the graph of f at (-p,1) and (p,1) respectively, and if L1 and L2 intersect at point x- and y- coordinates of Q in terms of p.
 
Physics news on Phys.org
O yeah I forgot. I got the a) part easily. Others I can't do.
 
For part b), try using that fact that [tex]0 = - 0[/tex] and the properties you should have deduced about the derivative of an even function.

For part c), just construct the two tangent lines. You have enough information to do this if you use the symmetry of the function and its derivative.
 
Thanks man. I appreciate it.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
Replies
8
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K