Solving a Simple Differential Equation: y' = (x + xy^2)

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
S[e^x]=f(u)^n
Messages
23
Reaction score
0

Homework Statement


i'm trying to solve the simple differential equation y'=(x+xy^2)


2. The attempt at a solution

i get dy/(1+y^2)=xdx and then integrate over the whole thing getting the solution

arctan(y)=0.5x^2+C

my problem is how do i simply this down to an equation in the form y=...

i must be missing something
 
Physics news on Phys.org
S[e^x]=f(u)^n;1635559 said:

Homework Statement


i'm trying to solve the simple differential equation y'=(x+xy^2)


2. The attempt at a solution

i get dy/(1+y^2)=xdx and then integrate over the whole thing getting the solution

arctan(y)=0.5x^2+C

my problem is how do i simply this down to an equation in the form y=...

i must be missing something
well remember that if [tex]tan(x)=y[/tex] then [tex]arctan(y)=x[/tex] does this help u? Tan and arctan are inverse functions so, tan(arctan x)=x
 
Last edited:
but that x only valid under certain bounds right? and I'm having trouble figuring out what those are