- #1
Nano-Passion
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I feel that it may be redundant to rewrite the whole problem. I just need to know how the book got from point to point b.
The book says that
[tex]e^{-3x} \frac{dy}{dx} - 3y (e^{-3x}) = 0[/tex]
is the same as [tex]\frac{d}{dx}(e^{-3x}y) = 0[/tex]
How? I tried dividing and multiplying by some variables to get the same expression but all was in vain.
The book says that
[tex]e^{-3x} \frac{dy}{dx} - 3y (e^{-3x}) = 0[/tex]
is the same as [tex]\frac{d}{dx}(e^{-3x}y) = 0[/tex]
How? I tried dividing and multiplying by some variables to get the same expression but all was in vain.
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