Solving a Skier's Horizontal Distance Problem

[A PP4L K]

Homework Statement

A skier starts from rest at the top of a hill that is inclined at 10.5degrees with the horizontal. The hillside is 200 m long, and the coefficient of friction between the skis is 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest?

Homework Equations

F_f=μF_norm
F_net=ma
cosθ=adj/hyp
sinθ=opp/adj
tanθ=opp/adj

The Attempt at a Solution

μ = .075
d = 200m
incline = 10.5°

I know I must use components to solve, but the way this problem is set up (lack of givens) I am having trouble solving it. Also I do not know how to calculate it once he hits horizontal land and is no longer on the slope. A walk-through of this would be absolutely AMAZING! :)

 

[gneill]

Homework Statement

A skier starts from rest at the top of a hill that is inclined at 10.5degrees with the horizontal. The hillside is 200 m long, and the coefficient of friction between the skis is 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest?

Homework Equations

F_f=μF_norm
F_net=ma
cosθ=adj/hyp
sinθ=opp/adj
tanθ=opp/adj

The Attempt at a Solution

μ = .075
d = 200m
incline = 10.5°

I know I must use components to solve, but the way this problem is set up (lack of givens) I am having trouble solving it. Also I do not know how to calculate it once he hits horizontal land and is no longer on the slope. A walk-through of this would be absolutely AMAZING! :)

You'll have to be more specific about what you think is missing from the givens. It looks okay to me.

 

[zorro]

Its a very very easy question!
All data required is given. You just need one equation to solve it. Think more about it.