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This isn't homework, so there's no rush, or a necessity to find the answer but I'd like input into helping me solve this problem. I constructed this problem from an Australian Mathematics competition that instead used simple numbers in place of the variables I'm replacing them with.

I'll describe it as best as I can:

In the x-y plane, there is a square of side lengths

http://img198.imageshack.us/img198/7304/pfsquaren.png

Find an expression for m in terms of s,d and n.

I've barely scratched the surface of this problem...

All I can really think of is that m is restricted to [itex]0<m<s/d[/itex].

Any ideas to possibly help nudge me in a direction are welcome. Anything is helpful, even if you don't feel like you're right

## Homework Statement

I'll describe it as best as I can:

In the x-y plane, there is a square of side lengths

*s*that has it's closest vertex located a distance d from the origin, and it is sitting on the x-axis in the first quadrant. There is a line y=mx that cuts the square in the ratio [tex]\frac{A_1}{A_2}=n[/tex] where*A*is the area of the section in the square that is above the line, and_{1}*A*the area below the line. n can take any value that is meaningful, in this case, all real positive values (thus_{2}*A*and_{1}*A*will have a value larger than 0)._{2}http://img198.imageshack.us/img198/7304/pfsquaren.png

Find an expression for m in terms of s,d and n.

## The Attempt at a Solution

I've barely scratched the surface of this problem...

All I can really think of is that m is restricted to [itex]0<m<s/d[/itex].

Any ideas to possibly help nudge me in a direction are welcome. Anything is helpful, even if you don't feel like you're right

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