Why Does Calculating Train Engine Power Result in Different Values?

Click For Summary
SUMMARY

The calculation of train engine power traveling at 50 meters per second with a total resistance of 30 KiloNewtons results in a power output of 1.5 Mega Watts. However, the answer book states 1.47 Mega Watts, which is derived by incorrectly subtracting the resistance from the calculated power. The discussion highlights that force and power are different units and cannot be directly subtracted. Additionally, gravity does not affect the power calculation for a level track, indicating potential errors in the source material.

PREREQUISITES
  • Understanding of basic physics concepts, specifically force and power calculations.
  • Familiarity with units of measurement, particularly Mega Watts and KiloNewtons.
  • Knowledge of the relationship between velocity, force, and power.
  • Basic grasp of gravitational effects on motion in a horizontal context.
NEXT STEPS
  • Research the principles of power calculation in physics, focusing on the formula Power = Force x Velocity.
  • Study the differences between force and power, including their units and applications.
  • Explore common errors in physics textbooks and how to identify them.
  • Investigate the effects of rolling resistance on train performance and power requirements.
USEFUL FOR

Students studying physics, engineers involved in train design, and anyone interested in understanding the mechanics of train power calculations.

Bix
Messages
8
Reaction score
1
How did you find PF?: Online

[Thread moved from the New Member Intro forum, so no Schoolwork Template is shown]

Hi. I'm new and am trying to solve a simple question 'Find the max power of a train engine traveling level at 50 metres per second if total resistance to motion is 30 KiloNewtons.

I get power = force times velocity so 30000 x 50 = 1500000 = 1.5 Mega Watts. My answer book says 1.47 Mega Watts. I can see how 1.5MW minus 30KW = 1500000 - 30000 = 1.47MW. Also I can see that power times gravity of 9.8 = 1.5 MW times 9.8 N gives the same answer.

I can't see how you should subtract the force from the sum of the force and the distance, or how vertical gravity can reduce the speed of a horizontally moving train. Thanks :)
 
Last edited by a moderator:
Physics news on Phys.org
Your math seems fine. Subtracting 30KW doesn't make sense since 30KW hasn't been computed anywhere, making it a random number. Subtracting the force doesn't make sense since force and power are different units and cannot be added. And yes, gravity plays no role since the problem says 'level'. Also 1.5MW * 9.8 m/sec² results in 14.7 mega-something, not 1.47 mega-something.

I cannot explain the book answer.
 
I think these book/web errors often arise when someone modifies the question and fails to check the answer given elsewhere.
That 9.8 produces the right leading digits is suggestive. The original might have been something like "a train of mass 30,000 kg and rolling resistance (or "rolling friction" or whatever) of 0.1..."
 
  • Like
Likes   Reactions: berkeman
Thanks guys, massively appreciated :)
Interesting insight haruspex..
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
116K
Replies
1
Views
5K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 69 ·
3
Replies
69
Views
16K