Solving a Tricky Natural Log Question

[Weather Freak]

I have a tricky natural log in front of me.

It's ln(1/x).

The reason it's tricky is because I thought that I could re-write it as ln(1)-ln(x), as per the rules of logs, but that doesn't seem to agree with my calculator. Is there a reason why?

Thanks!

 

[emptymaximum]

you put it in your calculator wrong?

 

[moose]

Works just fine for me. Check your parenthesis or something

 

[HallsofIvy]

I have a tricky natural log in front of me.
It's ln(1/x).
The reason it's tricky is because I thought that I could re-write it as ln(1)-ln(x), as per the rules of logs, but that doesn't seem to agree with my calculator. Is there a reason why?
Thanks!

And of course, log(1)= 0 so this is -ln(x). You could also have used the "power rule" to say ln(1/x)= ln(x^-1)= -ln(x).

Is that what your calculator is giving you? Remember- you are supposed to be smarter than your calculator!