How to Solve a Trig Equation for x with Cosine and Sine Terms

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To solve the equation cos^2x + 2sin^2x = -1, it is important to recognize that cos^2x + sin^2x = 1 can be utilized. By substituting cos^2x with 1 - sin^2x, the equation can be rewritten as 1 + sin^2x = -1. This leads to the conclusion that sin^2x = -2, which is not possible since the square of a sine function cannot be negative. Therefore, there are no real solutions for x in this equation.
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Homework Statement


cos^2x+2sin^2x=-1

Solve for x

Homework Equations





The Attempt at a Solution


I don't really know how to start. I know cos^2x+sin^2x=1 but I don't think I can apply that with the 2 thrown in there.
 
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Observe: cos^2 + 2 sin^2 = (cos^2 + sin^2) + sin^2
 
thank you
 
Or, if it weren't quite that obvious, you could have replaced cos^2(x) with 1- sin^2(x). That is, cos^2(x)+ 2sin^2(x)= (1- sin^2(x))+ 2sin^2(x)= 1+ sin^2(x)= 1.
 

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