Solving Algebra: How do we go from 1 to 2?

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SUMMARY

The discussion focuses on the transition from the equation 1 -x(t)= −Bω2 cos(ωt) −Cω2 sin(ωt) to 2 - x(t)=−ω2 x(t). The key clarification provided is that the correct form of the equations involves the second derivative of x(t), denoted as x''(t), which leads to the conclusion that x''(t) = −ω2 x(t). This indicates a relationship between the second derivative of the function and the original function, essential in solving differential equations in algebra.

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jimmy42
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Hello,

I am having some problem with some algebra:

1 -x(t)= −Bω2 cos(ωt) −Cω2 sin(ωt)
2 - x(t)=−ω2 x(t)

Can someone explain how we went from 1 to 2?

Thanks.
 
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hello jimmy! :smile:

i'll guess that that should read …

0 x(t)= Bcos(ωt) + Csin(ωt)

1 x''(t)= -Bω2cos(ωt) - Cω2sin(ωt)

2 x''(t) = −ω2x(t) :wink:
 

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