Solving Algebraically: Finding an x Intercept of Two Functions

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Homework Help Overview

The discussion revolves around finding the x-intercept of the equation x = 200sin(πx/120), which is related to introductory integration concepts. Participants explore the algebraic and graphical methods of solving this equation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the difficulty of solving the equation algebraically, with some suggesting it may not have an algebraic solution. Others question the definition of algebraic in this context and explore the possibility of rearranging the equation for x.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have offered insights into the nature of transcendental equations and iterative methods, while others express uncertainty about the solvability of the equation.

Contextual Notes

There is mention of the instructor's comment regarding the complexity of solving the equation algebraically, and participants are navigating the implications of using terms like "algebraically" and "unsolvable." The original poster indicates that they are not required to post a formal attempt, as this is not a homework problem.

jrand26
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Hi guys

What I have isn't really a 'homework problem', but I thought I'd post it here anyway. We're doing sort of an introduction to integration currently (areas between curves, u substititon etc) and one of the problems we had involved finding the x intercept of two functions first. It ended up being

x = 200sin (pi x/120)

Our instructor told us that that was very difficult to solve algebraically and required the use of 'very fancy maths'. We just solved it graphically and continued on, but I would be interested to see the solution found algebraically.

I won't bother posting my attempt, as it isn't a homework problem I don't feel the need. I hope that's alright.
 
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From what I've heard being said quite a few times on this forum, there is no algebraic solution as of the present for such an equation. Whether this means there is some very complicated mathematical process or none at all (I believe the latter), then there is no way you, or many others will understand how it works.
 
And what do you need to solve here? Is pi(x) function?
 
The equation sin(x)=x (and many variations on it) is called a transcendental equation. What that means is that there is no algebraic solution, i.e. a solution in which only common algebraic functions such as addition, multiplication, are used. While the meaning of algebraic changes based on context, it usually includes polynomials, sine and cosine, and exponential and logarithm functions, and that's about it.

As a straight up example, I could define w(x) to be the inverse function of [tex]\frac{x}{200sin(\frac{ \pi x } {120})}[/tex] and then your solution would be x=w(1). This exact technique is used on some equations, but for obvious reasons usually isn't very instructive
 
Thanks for replying.

Дьявол said:
And what do you need to solve here? Is pi(x) function?

Need to solve for x.

So are you guys are saying that this equation is 'unsolvable'?
I may have used the term 'algebraically' incorrectly. What I meant to ask is that can you rearrange for x and get the answer out (answer is 100 iirc).
 
Last edited:
jrand26 said:
So are you guys are saying that this equation is 'unsolvable'?
I may have used the term 'algebraically' incorrectly. What I meant to ask is that can you rearrange for x and get the answer out (answer is 100 iirc).

It's like Office_Shredder said, there is no way you could use normal multiplication or subtraction or factorization and such things you'd normally use to solve the equation.

You could make an iterative formula such as

[tex]x_{n+1}=200sin(\frac{\pi x_n}{120})[/tex]

then find a suitable interval where you think the root lies, and then choose an x1, find x2,x3 and when you find the 'x' values are the same, you can take the root as that number.
 
Interesting, thanks for your help.
 

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