Solving an Equation: Rearranging Numbers Around

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SUMMARY

The discussion focuses on rearranging the identity e^{i\pi} + 1 = 0 to derive i^{i} = e^{-\frac{\pi}{2}}. The user attempts to isolate 1 and take the square root, leading to the equation \sqrt{e^{i\pi}} = \sqrt{-1}. Participants suggest raising both sides to the power of i to further manipulate the equation, emphasizing the importance of correctly applying exponent rules and understanding complex numbers.

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  • Study the derivation of Euler's identity e^{i\pi} + 1 = 0
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Homework Statement


Okay, yesterday in class my teacher gave me this identity e^{i\pi }+1=0
and she wants me to rearrange the numbers around, so I can get this i^{i}= e^{-\frac{\pi}{2}}


Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this \sqrt{e^{i\pi }}= \sqrt{-1}
But this is the question what do I do after that ?
 
Last edited:
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xvtsx said:

Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this \sqrt{e^{i\Pi }}= \sqrt{-1}
But this is the question what do I do after that ?

Do you know another way to write

\sqrt{e^{i \pi}}?

Do you know another way to write

\sqrt{-1}?
 
Hi xvtsx! :smile:

(have a pi: π and try using the X2 tag just above the Reply box :wink:)

Raise each side of your last equation to the power of i. :smile:
 
Hmm.. do I raise to the power of i after I change the square root for \frac{1}{2} and multiple it with iπ ?
 
Last edited:
(what happened to that π i gave you? :redface:)

Yes, (eiπ/2)i = … ? :smile:
 
sorry for the pi part, but I use the latex editor and it only gaves that one xD.. thanks by the way. :)
 

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