Solving an Integral with Wave Packet: Find \varphi(k)

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Homework Help Overview

The discussion revolves around evaluating the integral of a wave packet defined as \varphi(k) = \int B(k)\cos(kx) dk, where B(k) = exp(-a²k²), over the interval from 0 to infinity. Participants are exploring the implications of the integrand's properties and the challenges posed by the resulting expressions involving error functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the even nature of the integrand and consider extending the limits of integration. There are inquiries about alternative methods to evaluate the integral without resorting to error functions, as well as suggestions to express cosine in terms of exponential functions to facilitate evaluation.

Discussion Status

The discussion is ongoing, with participants sharing insights about the integral's properties and exploring different approaches. Some guidance has been offered regarding the use of Fourier transforms, but there is no consensus on a definitive method to avoid error functions.

Contextual Notes

Participants are grappling with the limitations imposed by the integral's structure and the specific functions involved, particularly the presence of error functions in their attempts to evaluate the integral.

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Homework Statement



Consider the wave packet \varphi(k) = \int B(k)cos(kx) dk from 0 to infinity and B(k) = exp(^{-a^{2}k^{2}}). Find \varphi(k)


Homework Equations





The Attempt at a Solution



After looking up integral tables, i got an expression involving error function (erf) and imaginary error function (erfi) which i don't know how to continue.
 
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The integrand is an even function, so you can write

\int_0^\infty B(k)\cos(kx)\,dk = \frac{1}{2}\int_{-\infty}^\infty B(k)\cos(kx)\,dk

Does that help?
 
vela said:
The integrand is an even function, so you can write

\int_0^\infty B(k)\cos(kx)\,dk = \frac{1}{2}\int_{-\infty}^\infty B(k)\cos(kx)\,dk

Does that help?

But i will still end up with those error function which i can't evaluate. Is there any method which does not involve the error function?
 
But i will still end up with those error function. Is there any method which will not involve the error functions?
 
Not really, but you can evaluate the integral exactly because of the limits.

There is another approach you can try: Write cos kx as the real part of eikx. Then the integral is a Fourier transform, which you can look up in a table.
 
Last edited:

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