Solving an Odd Function with Periodicity

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SUMMARY

The discussion centers on solving for the expression f(75) - f(-30) given that f(x) is an odd function with a period of τ=7. The solution utilizes the periodicity property to simplify the expression to f(5) + f(2). A key insight shared is the relationship between f(5) and f(2), emphasizing that since f is odd, f(-2) = -f(2), leading to further simplification.

PREREQUISITES
  • Understanding of odd functions and their properties
  • Knowledge of periodic functions and their implications
  • Familiarity with function transformations and reductions
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of odd functions in detail
  • Explore periodic functions and their applications in trigonometry
  • Learn about function transformations and their effects on graphs
  • Practice solving problems involving periodicity and odd functions
USEFUL FOR

Students studying mathematics, particularly those focusing on functions, periodicity, and algebraic manipulation. This discussion is beneficial for anyone preparing for exams involving these concepts.

billy1024
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Homework Statement



Basically, I had a test yesterday and one of the questions was:

"an odd function f(x) has a period τ=7. What is the value of f(75)-f(-30)"

Homework Equations



n/a

The Attempt at a Solution



I used periodicity to reduce

= f(75-70) + f(30-28)
= f(5) + f(2)

What else could I have done?
 
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welcome to pf!

hi billy1024! welcome to pf! :smile:
billy1024 said:
I used periodicity to reduce

= f(75-70) + f(30-28)
= f(5) + f(2)

What else could I have done?

hint: what is the relation between f(5) and f(2) ? :wink:
 
since f is odd, f(-2) = -f(2), so f(2) = -f(-2).

what is 5 - (-2)?
 

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