Solving Atwood's Machine: Find Accel & Time for 60 cm

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SUMMARY

The discussion focuses on solving an Atwood's Machine problem involving a solid cylindrical pulley with a mass of 80 g and a radius of 10 cm, where a 1.1 kg mass and a 1.05 kg mass are suspended on either side. The acceleration of the system was successfully calculated, and the next step is to determine the time taken for the masses to travel a distance of 60 cm. The relevant equation to find the time, given constant acceleration, is derived from the kinematic equation: \(d = \frac{1}{2} a t^2\), where \(d\) is the distance, \(a\) is the acceleration, and \(t\) is the time.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with kinematic equations
  • Basic knowledge of rotational dynamics
  • Ability to perform unit conversions (e.g., grams to kilograms)
NEXT STEPS
  • Learn how to apply kinematic equations to solve for time in uniformly accelerated motion
  • Study the principles of rotational dynamics and their application in pulley systems
  • Explore the derivation of the kinematic equation \(d = \frac{1}{2} a t^2\)
  • Investigate the effects of friction and mass distribution on Atwood's Machine
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of Atwood's Machine problems.

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Homework Statement



An Atwood’s Machine has a solid cylindrical pulley with a mass of 80 g and a radius of 10 cm. A 1.1 kg mass is hung on one side and a 1.05 kg mass on the other side. Find the acceleration of the two masses, and the time for them to travel a distance of 60 cm.

2. The attempt at a solution

I was successful in finding the acceleration of the first part of the question now can someone help me pinpoint a equation to solve the 2nd part?
 
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If you know the acceleration of a body and if the acceleration is constant can you not find the distance covered in t seconds.If u can then put the value of the distance i.e 60 cm in the equation and solve for t.
 

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