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Solving Beam Deflection with Singularity Equations
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[QUOTE="PhanthomJay, post: 6054895, member: 58874"] I think you mean calculating the [I]reaction[/I] forces at the supports. It is equal to 2 M_o + R_a(L), assuming cw moments are positive and R_a acts upward. In your first attempt, you assumed that clockwise moments are negative, and you assumed that R_a acts upward, producing a clockwise or negative moment about B. This is Ok. But when you solved R_a and got a negative value for it, that means you assumed the wrong direction for it, so R_a acts downward on the beam. R_b must act upward, for equilibrium The applied moments are sometimes called couples, and act about the z axis. You might think of them as a torque tightening a bolt at the face of the beam at the far ends. Moments convention can be positive clockwise or negative clockwise, your choice. In engineering , cw moments are most often considered positive, by convention. the direction of the reaction forces at the supports as caused by the moments has already been addressedby the right hand rule, the moments shown act about the z axis, and cause bending in the xy plane. Often an isometric 3D sketch is required for moments applied about other axes. The reaction force does not cause the moment, it's just the opposite. Sometimes the applied moments are given as force couples...2 equal and opposite forces a perpendicular distance apart. Don't confuse these forces with the support reaction forces. [/QUOTE]
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Solving Beam Deflection with Singularity Equations
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