Solving Complex Integrals Using the Residue Theorem on Circular Contours

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The discussion focuses on evaluating complex integrals using the Residue Theorem on circular contours. The first integral, ∫C (z)/(z²+9) dz, is evaluated along the contour │z-2i│=4, while the second integral, ∫C cos(z)/(z-1)³(z-5)² dz, is evaluated along the contour │z-4│=2. Participants highlight the importance of identifying poles within the contours to apply the Residue Theorem effectively, noting that the first integral has poles at ±3i and the second at 1 and 5.

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1. Evaluate ∫C (z)/z2+9 dz , where C is the circle │z-2i│=4.

what i have done so far is :

z(t) = 2i + 4eit
z'(t) = 4ieit
f(z(t)) = 4ieit/(4ieit)2+9

∫ (4ieit/(4ieit)2+9) (4ieit) dt

intergrate from 0->2pi

but i don't know how to solve this intergral, can anyone help?

2. ∫c cos(z)/(z-1)^3(z-5)^2 dz , where C is the circle │z-4│=2.

this z'(t) = 0
so , is this intergral equal 0?
since f(z(t))(z'(t)) = 0


Thanks
 
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Shouldn't you be using the residue theorem to evaluate the integrals?

(Note that (1) has poles at ±i3, and (2) has poles at 1 & 5. Which of those lie within the given contours?)
 

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