Solving Complex Log Derivatives: y = log_2(x^2+1)

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SUMMARY

The discussion focuses on finding the derivative of the function y = log₂(x² + 1). The correct derivative is established as y' = 2x / ((x² + 1) ln(2)), derived using the formula for the derivative of a logarithm and applying the chain rule. Participants clarify the distinction between natural logarithm (ln) and base-2 logarithm (log₂), emphasizing the importance of using the correct logarithmic base in calculations. The conversation also highlights the utility of Wolfram Alpha for verifying derivatives.

PREREQUISITES
  • Understanding of logarithmic differentiation
  • Familiarity with the chain rule in calculus
  • Knowledge of natural logarithms (ln) versus base-2 logarithms (log₂)
  • Basic proficiency in using computational tools like Wolfram Alpha
NEXT STEPS
  • Study the properties of logarithmic functions in calculus
  • Learn more about the chain rule and its applications in differentiation
  • Explore advanced differentiation techniques for complex functions
  • Utilize Wolfram Alpha for verifying calculus problems and derivatives
USEFUL FOR

Students studying calculus, educators teaching differentiation techniques, and anyone looking to deepen their understanding of logarithmic derivatives.

iamsmooth
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Homework Statement


y = \log_{2}(x^2 + 1)<br />

Homework Equations


I think the pattern is:

<br /> \frac{d}{dx}[\log_{b}(x)] = \frac{1}{x ln(b)}

The Attempt at a Solution



<br /> y\prime = \frac{2x}{(x^2+1)ln(2)}

I did this by applying the pattern (that may or may not be correct) and then chain ruling the middle. If this is correct, then would this amount of work be acceptable (as you can kind of eye it without doing much work)?

When we do weird functions like y=x^x^2 I know how to do them by taking the ln of both sides and playing around with log properties, since this is the only kind of question that came up on quizzes, it's the only kind of log derivatives I'm familiar with.

Anyways, thanks.
 
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Is there a reason why the denominator log(2) instead of ln(2)?

ln(x) != log(x), no?

Thanks for the webpage, seems awesomely useful for future reference.
 


First line below the derivative states "log(x) is the natural logarithm"...
 


Oh whoops, sorry.

Thanks a lot, appreciate the timely help :D
 
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