- #1

chwala

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- Homework Statement
- kindly see attached below:

- Relevant Equations
- ##y=vx##

this is pretty easy for me to solve, no doubt on that. My question is on the constant. Alternatively, is it correct to have,

##ln x= \frac {v^2}{2}##+ C, then work it from there...

secondly, we are 'making" ##c= ln k##, is it for convenience purposes?, supposing i left the constant as it is, would that be wrong?

##ln x= \frac {v^2}{2}##+ C

##ln x-c= \frac {v^2}{2}##

##2[ln x-c]=v^2##

##2x^2[ln x-c]=y^2## would this be correct?...the question that i am trying to ask is, does it matter where one places the constant after integration.

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