- #1
chwala
Gold Member
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- Homework Statement
- kindly see attached below:
- Relevant Equations
- ##y=vx##
this is pretty easy for me to solve, no doubt on that. My question is on the constant. Alternatively, is it correct to have,
##ln x= \frac {v^2}{2}##+ C, then work it from there...
secondly, we are 'making" ##c= ln k##, is it for convenience purposes?, supposing i left the constant as it is, would that be wrong?
##ln x= \frac {v^2}{2}##+ C
##ln x-c= \frac {v^2}{2}##
##2[ln x-c]=v^2##
##2x^2[ln x-c]=y^2## would this be correct?...the question that i am trying to ask is, does it matter where one places the constant after integration.
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