Solving Computations w/ Cycles: Permutations, Inverses, Orders

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Discussion Overview

The discussion revolves around finding the product and inverse of permutations in the symmetric group S9. Participants explore the computation of cycles, addressing both the direct product of permutations and the concept of inverses.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses confusion about finding the product and inverse of a given permutation, detailing their steps and resulting cycles.
  • Another participant provides a step-by-step breakdown of the permutation calculations, confirming the cycles (1 3 8 5 9) and (2 6 4), while noting that the cycle (7) may not need to be included.
  • A later reply suggests that characters unchanged by a permutation do not need to be mentioned, proposing a simplified notation for the result.
  • Participants discuss the method for finding the inverse of a permutation, with one suggesting to "just go backwards."

Areas of Agreement / Disagreement

There is no explicit consensus on the inclusion of the cycle (7) in the final answer, as some participants suggest it may not be necessary. The method for finding inverses is briefly mentioned but not elaborated upon in detail.

Contextual Notes

Participants do not clarify certain assumptions regarding the treatment of unchanged elements in permutations or the specific conventions used for notation.

CoachBryan
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So I've been sitting here for a while looking at my study guide and I am not sure how to find the product (or even the inverse) of this permutation in S9:

(2 5 1 3 6 4) (8 5 6)(1 9) = (1 3 8 5 9)(2 6 4) (Correct answer)

I know it starts off with 1 --> 3, then you get (1 3 and then after you continue with 3 --> 6 --> 8. After you start with 6 --> 4, right? But I keep coming across the wrong answer. I get (1 3 8 4 2) (8 1)

I'm pretty confused on this topic. If you could shed some light I'd greatly appreciate it. Thanks!
 
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Well, it was a long time ago I did those things, but, assuming that the permutations should be performed from left to right, I get:

1 --> 3 --> 3 --> 3
3 --> 6 --> 8 --> 8
8 --> 8 --> 5 --> 5
5 --> 1 --> 1 --> 9
9 --> 9 --> 9 --> 1

leading to the cycle (1 3 8 5 9)

2 --> 5 --> 6 --> 6
6 --> 4 --> 4 --> 4
4 --> 2 --> 2 --> 2

leading to the cycle (2 6 4)

7 --> 7 --> 7 --> 7

leading to the cycle (7)

So, the answer is (1 3 5 8 9)(2 6 4)(7)

but (7) needs perhaps not be included, or maybe the elements to be permuted don't even include 7. In any case, the book's answer is correct.
 
Erland said:
Well, it was a long time ago I did those things, but, assuming that the permutations should be performed from left to right, I get:

1 --> 3 --> 3 --> 3
3 --> 6 --> 8 --> 8
8 --> 8 --> 5 --> 5
5 --> 1 --> 1 --> 9
9 --> 9 --> 9 --> 1

leading to the cycle (1 3 8 5 9)

2 --> 5 --> 6 --> 6
6 --> 4 --> 4 --> 4
4 --> 2 --> 2 --> 2

leading to the cycle (2 6 4)

7 --> 7 --> 7 --> 7

leading to the cycle (7)

So, the answer is (1 3 5 8 9)(2 6 4)(7)

but (7) needs perhaps not be included, or maybe the elements to be permuted don't even include 7. In any case, the book's answer is correct.
Thanks a lot! Now it makes sense. Do you know how to find the inverse?
 
CoachBryan said:
Thanks a lot! Now it makes sense. Do you know how to find the inverse?
Just go backwards!
 
The convention that I am familiar with is that if a character is not changed by a permutation, it doesn't need to be mentioned.
So your (1 3 5 8 9)(2 6 4)(7) can be written as (1 3 5 8 9)(2 6 4).
 
Thanks guys! On the inverse problem as well. Appreciate it.
 

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