Solving Cyclotron Movement Problem with 500V and 0.790B

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A cyclotron with a 61.0 cm diameter operates using a 500 V potential difference and a magnetic field strength of 0.790 T. The problem involves calculating the number of revolutions a proton makes before exiting the cyclotron. The user has determined the maximum speed and kinetic energy but is struggling to derive the total number of revolutions. Additional insights are requested on how the cyclotron functions and the conditions under which a proton would reach escape speed. Understanding the mechanics of the cyclotron is essential for solving the problem effectively.
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Homework Statement



A 61.0 cm diameter cyclotron uses a 500 V oscillating potential difference between the dees. The magnetic field strength is 0.790 ?

How many revolutions would a proton make before leaving the cyclotron?

Homework Equations



v/r=Bq/m Ke=1/2mv^2

The Attempt at a Solution



I am completely stumped on this problem, I have calculated the max speed, and therefor max kinetic energy. But cannot figure out how to derive number of revolutions from there.

Any hints would be greatly appreciated.

Thanks
 
Physics news on Phys.org
Canadian,

Why would the electron leave the cyclotron,
Describe first how this device works.
How does the electron reach the escape speed?

Michel
 
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