- #1

Niles

- 1,866

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## Homework Statement

Hi.

I want to solve:

[tex]

\frac{d\ln(-x)}{dx}.

[/tex]

When using the chain rule I get:

[tex]

\frac{d \ln(-x)}{dx} = \frac{d\ln(-x)}{d(-x)}\frac{d(-x)}{dx} = -\frac{d\ln(-x)}{d(-x)}.

[/tex]

But how do I find the last derivative? I know by experience that it is -x

^{-1}, but how is the derivation done?

Thanks in advance.